忧郁之子
PHP获得跳转的真实地址实例
现在有很多的短网址应用,点击就跳转到缩短之前的网址了,那今天我们就来看一下,PHP如何获取短网址跳转之前的网址,其实也很简单,就是用php的get_headers 函数,取得Response Headers,之后慢慢分析就行了。
给出具体实现方法,代码如下:
<?php
$header = get_headers($url, 1);
if (strpos($header[0], '301') || strpos($header[0], '302')) {
if (is_array($header['Location'])) {
return $header['Location'][count($header['Location']) - 1];
} else {
return $header['Location'];
}
} else {
return $url;
}
?>
实例二,代码如下:
<?php
echo get_redirect_url('https://www.xysoft.cc/');
//输出结果为:http://code.google.com/android/
function get_redirect_url($url) {
$redirect_url = null;
$url_parts = @parse_url($url);
if (!$url_parts) return false;
if (!isset($url_parts['host'])) return false; //can't process relative URLs
if (!isset($url_parts['path'])) $url_parts['path'] = '/';
$sock = fsockopen($url_parts['host'], (isset($url_parts['port']) ? (int)$url_parts['port'] : 80) , $errno, $errstr, 30);
if (!$sock) return false;
$request = "HEAD " . $url_parts['path'] . (isset($url_parts['query']) ? '?' . $url_parts['query'] : '') . " HTTP/1.1rn";
$request.= 'Host: ' . $url_parts['host'] . "rn";
$request.= "Connection: Closernrn";
fwrite($sock, $request);
$response = '';
while (!feof($sock)) $response.= fread($sock, 8192);
fclose($sock);
if (preg_match('/^Location: (.+?)$/m', $response, $matches)) {
if (substr($matches[1], 0, 1) == "/") return $url_parts['scheme'] . "://" . $url_parts['host'] . trim($matches[1]);
else return trim($matches[1]);
} else {
return false;
}
}